Optimal. Leaf size=341 \[ -\frac{(d+e x)^{7/2} (A b-a B)}{2 b (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}-\frac{(d+e x)^{5/2} (-7 a B e+3 A b e+4 b B d)}{4 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}+\frac{5 e (a+b x) (d+e x)^{3/2} (-7 a B e+3 A b e+4 b B d)}{12 b^3 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}+\frac{5 e (a+b x) \sqrt{d+e x} (-7 a B e+3 A b e+4 b B d)}{4 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{5 e (a+b x) \sqrt{b d-a e} (-7 a B e+3 A b e+4 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{9/2} \sqrt{a^2+2 a b x+b^2 x^2}} \]
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Rubi [A] time = 0.304423, antiderivative size = 341, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.171, Rules used = {770, 78, 47, 50, 63, 208} \[ -\frac{(d+e x)^{7/2} (A b-a B)}{2 b (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}-\frac{(d+e x)^{5/2} (-7 a B e+3 A b e+4 b B d)}{4 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}+\frac{5 e (a+b x) (d+e x)^{3/2} (-7 a B e+3 A b e+4 b B d)}{12 b^3 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}+\frac{5 e (a+b x) \sqrt{d+e x} (-7 a B e+3 A b e+4 b B d)}{4 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{5 e (a+b x) \sqrt{b d-a e} (-7 a B e+3 A b e+4 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{9/2} \sqrt{a^2+2 a b x+b^2 x^2}} \]
Antiderivative was successfully verified.
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Rule 770
Rule 78
Rule 47
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(A+B x) (d+e x)^{5/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx &=\frac{\left (b^2 \left (a b+b^2 x\right )\right ) \int \frac{(A+B x) (d+e x)^{5/2}}{\left (a b+b^2 x\right )^3} \, dx}{\sqrt{a^2+2 a b x+b^2 x^2}}\\ &=-\frac{(A b-a B) (d+e x)^{7/2}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left ((4 b B d+3 A b e-7 a B e) \left (a b+b^2 x\right )\right ) \int \frac{(d+e x)^{5/2}}{\left (a b+b^2 x\right )^2} \, dx}{4 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=-\frac{(4 b B d+3 A b e-7 a B e) (d+e x)^{5/2}}{4 b^2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(A b-a B) (d+e x)^{7/2}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (5 e (4 b B d+3 A b e-7 a B e) \left (a b+b^2 x\right )\right ) \int \frac{(d+e x)^{3/2}}{a b+b^2 x} \, dx}{8 b^2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{5 e (4 b B d+3 A b e-7 a B e) (a+b x) (d+e x)^{3/2}}{12 b^3 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(4 b B d+3 A b e-7 a B e) (d+e x)^{5/2}}{4 b^2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(A b-a B) (d+e x)^{7/2}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (5 e \left (b^2 d-a b e\right ) (4 b B d+3 A b e-7 a B e) \left (a b+b^2 x\right )\right ) \int \frac{\sqrt{d+e x}}{a b+b^2 x} \, dx}{8 b^4 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{5 e (4 b B d+3 A b e-7 a B e) (a+b x) \sqrt{d+e x}}{4 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e (4 b B d+3 A b e-7 a B e) (a+b x) (d+e x)^{3/2}}{12 b^3 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(4 b B d+3 A b e-7 a B e) (d+e x)^{5/2}}{4 b^2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(A b-a B) (d+e x)^{7/2}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (5 e \left (b^2 d-a b e\right )^2 (4 b B d+3 A b e-7 a B e) \left (a b+b^2 x\right )\right ) \int \frac{1}{\left (a b+b^2 x\right ) \sqrt{d+e x}} \, dx}{8 b^6 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{5 e (4 b B d+3 A b e-7 a B e) (a+b x) \sqrt{d+e x}}{4 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e (4 b B d+3 A b e-7 a B e) (a+b x) (d+e x)^{3/2}}{12 b^3 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(4 b B d+3 A b e-7 a B e) (d+e x)^{5/2}}{4 b^2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(A b-a B) (d+e x)^{7/2}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (5 \left (b^2 d-a b e\right )^2 (4 b B d+3 A b e-7 a B e) \left (a b+b^2 x\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a b-\frac{b^2 d}{e}+\frac{b^2 x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{4 b^6 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{5 e (4 b B d+3 A b e-7 a B e) (a+b x) \sqrt{d+e x}}{4 b^4 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{5 e (4 b B d+3 A b e-7 a B e) (a+b x) (d+e x)^{3/2}}{12 b^3 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(4 b B d+3 A b e-7 a B e) (d+e x)^{5/2}}{4 b^2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(A b-a B) (d+e x)^{7/2}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{5 e \sqrt{b d-a e} (4 b B d+3 A b e-7 a B e) (a+b x) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{9/2} \sqrt{a^2+2 a b x+b^2 x^2}}\\ \end{align*}
Mathematica [C] time = 0.113526, size = 111, normalized size = 0.33 \[ \frac{(a+b x) (d+e x)^{7/2} \left (\frac{e (a+b x)^2 (-7 a B e+3 A b e+4 b B d) \, _2F_1\left (2,\frac{7}{2};\frac{9}{2};\frac{b (d+e x)}{b d-a e}\right )}{(b d-a e)^2}+7 a B-7 A b\right )}{14 b \left ((a+b x)^2\right )^{3/2} (b d-a e)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.023, size = 1150, normalized size = 3.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (e x + d\right )}^{\frac{5}{2}}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.74298, size = 1447, normalized size = 4.24 \begin{align*} \left [-\frac{15 \,{\left (4 \, B a^{2} b d e -{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} +{\left (4 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (4 \, B a b^{2} d e -{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{\frac{b d - a e}{b}} \log \left (\frac{b e x + 2 \, b d - a e + 2 \, \sqrt{e x + d} b \sqrt{\frac{b d - a e}{b}}}{b x + a}\right ) - 2 \,{\left (8 \, B b^{3} e^{2} x^{3} - 6 \,{\left (B a b^{2} + A b^{3}\right )} d^{2} + 5 \,{\left (19 \, B a^{2} b - 3 \, A a b^{2}\right )} d e - 15 \,{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} + 8 \,{\left (7 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} -{\left (12 \, B b^{3} d^{2} -{\left (163 \, B a b^{2} - 27 \, A b^{3}\right )} d e + 25 \,{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{24 \,{\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}}, -\frac{15 \,{\left (4 \, B a^{2} b d e -{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} +{\left (4 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (4 \, B a b^{2} d e -{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{-\frac{b d - a e}{b}} \arctan \left (-\frac{\sqrt{e x + d} b \sqrt{-\frac{b d - a e}{b}}}{b d - a e}\right ) -{\left (8 \, B b^{3} e^{2} x^{3} - 6 \,{\left (B a b^{2} + A b^{3}\right )} d^{2} + 5 \,{\left (19 \, B a^{2} b - 3 \, A a b^{2}\right )} d e - 15 \,{\left (7 \, B a^{3} - 3 \, A a^{2} b\right )} e^{2} + 8 \,{\left (7 \, B b^{3} d e -{\left (7 \, B a b^{2} - 3 \, A b^{3}\right )} e^{2}\right )} x^{2} -{\left (12 \, B b^{3} d^{2} -{\left (163 \, B a b^{2} - 27 \, A b^{3}\right )} d e + 25 \,{\left (7 \, B a^{2} b - 3 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{12 \,{\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.27553, size = 645, normalized size = 1.89 \begin{align*} \frac{5 \,{\left (4 \, B b^{2} d^{2} e^{2} - 11 \, B a b d e^{3} + 3 \, A b^{2} d e^{3} + 7 \, B a^{2} e^{4} - 3 \, A a b e^{4}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right ) e^{\left (-1\right )}}{4 \, \sqrt{-b^{2} d + a b e} b^{4} \mathrm{sgn}\left ({\left (x e + d\right )} b e - b d e + a e^{2}\right )} - \frac{{\left (4 \,{\left (x e + d\right )}^{\frac{3}{2}} B b^{3} d^{2} e^{2} - 4 \, \sqrt{x e + d} B b^{3} d^{3} e^{2} - 17 \,{\left (x e + d\right )}^{\frac{3}{2}} B a b^{2} d e^{3} + 9 \,{\left (x e + d\right )}^{\frac{3}{2}} A b^{3} d e^{3} + 19 \, \sqrt{x e + d} B a b^{2} d^{2} e^{3} - 7 \, \sqrt{x e + d} A b^{3} d^{2} e^{3} + 13 \,{\left (x e + d\right )}^{\frac{3}{2}} B a^{2} b e^{4} - 9 \,{\left (x e + d\right )}^{\frac{3}{2}} A a b^{2} e^{4} - 26 \, \sqrt{x e + d} B a^{2} b d e^{4} + 14 \, \sqrt{x e + d} A a b^{2} d e^{4} + 11 \, \sqrt{x e + d} B a^{3} e^{5} - 7 \, \sqrt{x e + d} A a^{2} b e^{5}\right )} e^{\left (-1\right )}}{4 \,{\left ({\left (x e + d\right )} b - b d + a e\right )}^{2} b^{4} \mathrm{sgn}\left ({\left (x e + d\right )} b e - b d e + a e^{2}\right )} + \frac{2 \,{\left ({\left (x e + d\right )}^{\frac{3}{2}} B b^{6} e^{4} + 6 \, \sqrt{x e + d} B b^{6} d e^{4} - 9 \, \sqrt{x e + d} B a b^{5} e^{5} + 3 \, \sqrt{x e + d} A b^{6} e^{5}\right )} e^{\left (-3\right )}}{3 \, b^{9} \mathrm{sgn}\left ({\left (x e + d\right )} b e - b d e + a e^{2}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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